2sin^2x+1=4sinx

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Solution for 2sin^2x+1=4sinx equation:


Simplifying
2sin2x + 1 = 4sinx

Reorder the terms:
1 + 2in2sx = 4sinx

Solving
1 + 2in2sx = 4insx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4insx' to each side of the equation.
1 + -4insx + 2in2sx = 4insx + -4insx

Combine like terms: 4insx + -4insx = 0
1 + -4insx + 2in2sx = 0

Add '-1' to each side of the equation.
1 + -4insx + -1 + 2in2sx = 0 + -1

Reorder the terms:
1 + -1 + -4insx + 2in2sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4insx + 2in2sx = 0 + -1
-4insx + 2in2sx = 0 + -1

Combine like terms: 0 + -1 = -1
-4insx + 2in2sx = -1

Reorder the terms:
1 + -4insx + 2in2sx = -1 + 1

Combine like terms: -1 + 1 = 0
1 + -4insx + 2in2sx = 0

The solution to this equation could not be determined.

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